分组聚合后，怎么给TopHits中的列表数据排序

Elasticsearch | 作者张鹏 | 发布于2018年06月07日 | 阅读数：11968

java api查询我是这个使用的，现在查出来的结果数据过程如下：
TermsBuilder teamAgg= AggregationBuilders.terms("agg").field("person_id") .subAggregation( AggregationBuilders.topHits("top") .setFrom((params.getPageNo()-1)*params.getPageRows()).setSize(params.getPageRows()) ).minDocCount(Long.valueOf(1)) .size(Integer.valueOf(10));

Terms agg = response.getAggregations().get("agg");

for (Terms.Bucket entry : agg.getBuckets()) {

TopHits topHits = entry.getAggregations().get("top");
}

topHits 中数据根据时间字段排序该怎么排，目前是散乱的

5 个回复

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参考：

POST /sales/_search?size=0

{

    "aggs": {

        "top_tags": {

            "terms": {

                "field": "type",

                "size": 3

            },

            "aggs": {

                "top_sales_hits": {

                    "top_hits": {

                        "sort": [

                            {

                                "date": {

                                    "order": "desc"

                                }

                            }

                        ],

                        "_source": {

                            "includes": [ "date", "price" ]

                        },

                        "size" : 1

                    }

                }

            }

        }

    }

}

tophits结合sort

张鹏

还是不可以{
"query" : {
"bool" : {
"must" : [ {
"range" : {
"fcap_time" : {
"from" : 1528300800,
"to" : 1528387200,
"include_lower" : true,
"include_upper" : true
}
}
}, {
"bool" : {
"should" : {
"terms" : {
"fcap_dcid" : [ "f94bc77ef21e4c8bad38c8400e854c8b" ]
}
}
}
} ]
}
},
"explain" : true,
"sort" : [ {
"fcap_dcid" : {
"order" : "desc"
}
} ],
"aggregations" : {
"agg" : {
"terms" : {
"field" : "person_id",
"size" : 100,
"order" : {
"_term" : "desc"
}
},
"aggregations" : {
"top" : {
"top_hits" : {
"size" : 1,
"sort" : [ {
"fcap_time" : {
"order" : "desc"
}
} ]
}
},
"agg" : {
"terms" : {
"field" : "fcap_time",
"order" : {
"_term" : "desc"
}
}
}
}
}
}
}